calculate the mass of NaOH required to make 500ml of 0.5Molar aqueous solution
Molarity = number of moles/Volume in liters
=> Number of moles of NaOH = M * Vol
= 0.5*0.5
= 0.25
Mass required = Molar Mass * Number of moles
= 40 * 0.25
= 10g
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To calculate the mass of NaOH required to make a 0.5 Molar aqueous solution, you'll need to use the formula:
Molarity (M) = moles of solute / volume of solution in liters
Rearranging this formula, we have:
moles of solute = Molarity (M) × volume of solution in liters
Let's break down the calculation step by step:
Step 1: Convert the volume of the solution to liters.
500 mL = 500/1000 = 0.5 liters (since there are 1000 mL in 1 liter)
Step 2: Plug the values into the formula.
Moles of NaOH = 0.5 M × 0.5 L
Step 3: Calculate the moles of NaOH.
Moles of NaOH = 0.25 moles
Finally, to determine the mass of NaOH, you need to know the molar mass of NaOH. The molar mass of NaOH is the sum of the atomic masses of each element in the compound. Sodium (Na) has a molar mass of 22.99 g/mol, Oxygen (O) has a molar mass of 16.00 g/mol, and Hydrogen (H) has a molar mass of 1.01 g/mol. Adding these up, we get:
Molar mass of NaOH = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 39.00 g/mol
Step 4: Calculate the mass of NaOH.
Mass of NaOH = Moles of NaOH × Molar mass of NaOH
Mass of NaOH = 0.25 moles × 39.00 g/mol
The mass of NaOH required to make 500 mL of 0.5 Molar aqueous solution is 9.75 grams.