Television sizes are described by the length of their diagonal measure. What would be the listed size of the TV shown? (to the nearest whole inch)
A) 31 inches
B) 32 inches
C) 36 inches
D) 42 inches
The top portion of the tv is 28 in. and the side is 15.7 in.
My answer is C) 36. Inches
Using the pythagoras theorum,
x^2 = (28)^2 + (15.7)^2
x^2 = 784 + 246.5
x^2 = 1030.5
x = Root(1030.5) = 32
The answer is actually closer to B, 32 inches.
To determine the listed size of the TV shown, we can use the Pythagorean theorem. The diagonal of the TV can be found by using the formula: diagonal = √(side1^2 + side2^2).
Using the given measurements, we have:
side1 = 28 inches
side2 = 15.7 inches
Now, we can calculate the diagonal length:
diagonal = √(28^2 + 15.7^2)
diagonal ≈ √(784 + 246.49)
diagonal ≈ √1030.49
diagonal ≈ 32.06 inches
Rounding to the nearest whole inch, the listed size of the TV shown would be 32 inches. Therefore, the correct answer is B) 32 inches.
To determine the listed size of the TV, you can use the Pythagorean theorem which states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. In this case, the length of the diagonal is the hypotenuse, and the top portion and side of the TV form the other two sides of the right triangle.
Let's calculate the length of the diagonal:
Using the Pythagorean theorem, we can say:
Hypotenuse^2 = Side 1^2 + Side 2^2
In this case, the length of the diagonal is the hypotenuse, which is the unknown value we want to find. Side 1 is the top portion of the TV, given as 28 inches, and Side 2 is the side of the TV, given as 15.7 inches.
Plugging these values into the formula, we get:
Diagonal^2 = 28^2 + 15.7^2
Diagonal^2 = 784 + 246.49
Diagonal^2 = 1030.49
To find the length of the diagonal, we take the square root of both sides:
Diagonal = √1030.49
Diagonal ≈ 32.1 inches
Rounding to the nearest whole inch, the listed size of the TV shown would be B) 32 inches.