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if alpha and beta are the zero's of quadratic polynomial f(x) =x*x-x-2 find a polynomial who's zeros are 2 alpha +1 and 2 bita + 1 ?

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  1. You can factorize your given polynomial as follows:

    x^2 - x - 2 = 0
    => (x + 1)(x - 2) = 0
    The roots are thus x = 2, x = -1
    Alpha = 2, beta = -1

    Coming to the next part, (2alpha + 1) = 5, (2beta + 1) = -1

    You can thus use these roots to form the following polynomial:

    (x - 5)(x + 1) = 0
    => x^2 - 4x - 5 = 0

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