math

find the no of terms in an AP given that its first and last terms are a and 37a respectively and that its common difference is 4a

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  1. 37a = a + 9*4a
    so, ...

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  2. term(1) = a
    term(n)
    = a + (n-1)d
    = a + (n-1)(4a) = 37a

    (n-1)(4a) = 36a
    n-1 = 9
    n = 10

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