4/7 of the children in the hall are girls and the rest are boys. If there are 12 more girls

than boys, how many children are there in the hall?

If we take the total number of children in the hall as C, then,

Number of girls = (4/7)C
Number of boys = (3/7)C

We've also been given the difference, so:
(4/7)C - (3/7)C = 12
=> (4/7 - 3/7)C = 12
=> (1/7)C = 12
=> C = 12*7
=> C = 84

Thank you very much, Arora :].

To solve this problem, let's first set up an equation to represent the given information.

Let's denote the total number of children in the hall as "x".
Since 4/7 of the children are girls, we can say that the number of girls is (4/7)x.
And since the rest of the children are boys, we can say that the number of boys is (1 - 4/7)x, which simplifies to (3/7)x.
According to the problem, there are 12 more girls than boys, so we can set up another equation: (4/7)x = (3/7)x + 12.

To solve this equation, we can start by subtracting (3/7)x from both sides: (4/7)x - (3/7)x = 12.
This simplifies to (1/7)x = 12.

To isolate x, the total number of children, we divide both sides of the equation by (1/7): x = 12 / (1/7).
Dividing by a fraction is the same as multiplying by its reciprocal, so we have: x = 12 * (7/1).

Multiplying 12 by 7 gives us: x = 84.

Therefore, there are 84 children in the hall.