A gas occupies a volume of 200cm*cm*cm at a temperature of 27'C and 760mm pressure.Find the volume of gas at a temperature of -3'C at 760mm pressure?
the volume is proportional to the ABSOLUTE temperature (ºK)
200 cm^3 / (27 + 273) = v / (-3 + 273)
To solve this problem, you can use the combined gas law equation, which relates the initial and final conditions of the gas:
(P1 * V1) / (T1) = (P2 * V2) / (T2)
Where:
P1 = initial pressure
V1 = initial volume
T1 = initial temperature
P2 = final pressure
V2 = final volume
T2 = final temperature
First, let's assign the given values to the variables:
P1 = 760 mmHg (given)
V1 = 200 cm^3 (given)
T1 = 27°C (given)
P2 = 760 mmHg (given)
T2 = -3°C (given)
Now, we can plug these values into the formula and solve for V2:
(760 mmHg * 200 cm^3) / (27°C) = (760 mmHg * V2) / (-3°C)
Next, we can simplify the equation:
(760 * 200) / 27 = 760 * V2 / -3
Solve for V2:
V2 = [(760 * 200) / 27] * [-3 / 760]
V2 = 2000 cm^3
Therefore, the volume of the gas at a temperature of -3°C and 760 mmHg pressure is 2000 cm^3.