what would be a counterexample of this converse statement:

If a and b are even number, then a+b is a consecutive odd number.

contra example

a and b are 4 and 6
then a+b is 10 which is not odd.

Is this suppose to be something like..

(a-4 b-6)

a+b= ?

If so then it equals 10
cause 4+6=10

To find a counterexample for the given converse statement, we need to find a case where the hypothesis is true (a and b are even numbers), but the conclusion is false (a+b is not a consecutive odd number).

Let's consider a = 2 and b = 4. Both a and b are even numbers since they can be divided by 2 without a remainder. However, the sum of a+b is 6, which is not a consecutive odd number. Therefore, the counterexample to the converse statement "If a and b are even numbers, then a+b is a consecutive odd number" is a = 2 and b = 4.

To find a counterexample for the given converse statement, we need to find an example where both a and b are even numbers, but their sum (a+b) is not a consecutive odd number.

Let's try an example:
Let a = 2 and b = 4. Both a and b are even numbers.

a + b = 2 + 4 = 6

In this case, the sum (6) is not a consecutive odd number because it is even.

So, the counterexample to the converse statement "If a and b are even numbers, then a+b is a consecutive odd number" is when a = 2 and b = 4.