A 2.55-g piece of stainless steel absorbs 131J of heat when its temperature increases by 152°C. What is the specific heat of the stainless steel?
How do I do this???
heat in = C m (T2-T1)
find Sheat
131 in Joules = Sheat (in Joules/kg deg K) *(.00255 kg)*(152 deg K)
so
Sheat = 131 / (.00255*152) J/kg deg K
change in degrees K is the same as change in degrees C (K = C+273)
thanks
You are welcome.
To determine the specific heat of stainless steel, you need to use the equation:
q = m * c * ΔT
Where:
- q represents the heat absorbed or released by the substance (in joules)
- m is the mass of the substance (in grams)
- c is the specific heat capacity of the substance (in J/g°C)
- ΔT is the change in temperature (in °C)
In this case, you are given:
- q = 131 J (heat absorbed)
- m = 2.55 g (mass of the stainless steel)
- ΔT = 152 °C (change in temperature)
Now, we rearrange the equation to solve for c:
c = q / (m * ΔT)
Substituting the given values:
c = 131 J / (2.55 g * 152 °C)
Now, you can perform the calculation to find the specific heat of the stainless steel.