the width of a rectangle is 6 1/2 inches the length of the rectangle is 2wice its width. what is the perimeter of the rectangle?
6.5 inches + 13 inches + 6.5 inches + 13 inches = ?? inches
Can you think of an algebraic way to say all that?
2(6.5+2*6.5) = ?
how about 6*6.5 = 6*6 + 3 :) ?
To find the perimeter of a rectangle, we need to add up all four sides. In this case, we need to find the length and width in order to calculate the perimeter.
Let's start by finding the length of the rectangle. The problem states that the length is twice the width. If the width is 6 1/2 inches, we can multiply it by 2 to get the length:
Length = 2 * Width
Length = 2 * 6 1/2 inches
To solve this, we need to convert the mixed fraction to an improper fraction:
Length = 2 * (13/2) inches
Length = 26/2 inches
Length = 13 inches
Now that we know the length is 13 inches, we can proceed to find the perimeter.
Perimeter = 2 * (Length + Width)
To find the perimeter, we substitute the values:
Perimeter = 2 * (13 inches + 6 1/2 inches)
First, let's convert the mixed fraction to an improper fraction:
Perimeter = 2 * (13 inches + 13/2 inches)
Perimeter = 2 * (26/2 inches + 13/2 inches)
Now, let's add the fractions:
Perimeter = 2 * (39/2 inches)
Perimeter = 78/2 inches
Perimeter = 39 inches
Therefore, the perimeter of the rectangle is 39 inches.