Jennifer went to the post office for stamps. She bought the same number of 8 cents stamps and 10 cents stamps. She also bought as many 2 cents stamps as both of the other two combined. How many of each kind did she get if she paid a total of $4.40 for them all?
If she bought x 8-cent stamps, then
8x + 10x + 2*2x = 440
so then do 8x+10x+4x=22x and 440 / 22= 20
since x=20, he bought 20 8-cent stamps and 20 10-cent stamps and 40 2-cent stamps
Happy holidays to all of you :)
How come 160 + 200 + 80 = 240?? Fix ur math, bro.
what
I apologize for the error in my previous response. You are correct, the correct calculation should be:
20 * 8 = 160
20 * 10 = 200
40 * 2 = 80
Therefore, the correct total is 160 + 200 + 80 = 440. Thank you for pointing out the mistake.
Idk….
To solve this problem, we can break it down into steps. Let's assume Jennifer bought x number of 8 cent stamps, y number of 10 cent stamps, and z number of 2 cent stamps.
1. Based on the information given, Jennifer bought the same number of 8 cent stamps and 10 cent stamps. So we can say that x = y.
2. Jennifer also bought as many 2 cent stamps as both the 8 cent and 10 cent stamps combined. This means z = 2(x + y).
3. Lastly, we know that Jennifer paid a total of $4.40 for all the stamps. So we can write the equation: 8x + 10y + 2z = 440 (since all the amounts are in cents, we multiply the dollar value by 100).
Now, let's solve these equations simultaneously:
From equation 1, we have x = y.
Substituting this value in equation 3, we get: 8x + 10x + 2z = 440
Simplifying, we have: 18x + 2z = 440.
Now, using equation 2, where z = 2(x + y), we can substitute the value of z in equation 4: 18x + 2(2(x + y)) = 440
Expanding, we get: 18x + 4x + 4y = 440
Combining like terms, we have: 22x + 4y = 440.
Now, we have a system of two equations:
Equation 1: x = y
Equation 2: 22x + 4y = 440
To find the values of x and y, we can solve this system of equations using substitution or elimination method.
Let's use the elimination method to solve this system:
From equation 1, we can rewrite it as: x - y = 0.
Multiplying equation 1 by 4, we get: 4x - 4y = 0
Now, we can subtract this equation from equation 2 to eliminate y:
22x + 4y - (4x - 4y) = 440 - 0
Simplifying, we have: 18x + 8y = 440.
Now, let's solve the new equation:
18x + 8y = 440
Dividing both sides by 2, we get: 9x + 4y = 220.
We now have:
Equation 3: x - y = 0
Equation 4: 9x + 4y = 220.
Multiplying equation 3 by 4, we get: 4x - 4y = 0.
We can now add equation 4 to equation 3 to eliminate y:
9x + 4y + (4x - 4y) = 220 + 0
Simplifying, we have: 13x = 220.
Dividing both sides by 13, we get x = 220 / 13
Simplifying further, we have x = 16.92.
Since x represents the number of stamps, we can round it to the nearest whole number, making x = 17.
Now, substituting the value of x in equation 1, we have:
17 = y.
So Jennifer bought 17 of the 8 cent stamps, 17 of the 10 cent stamps, and z number of the 2 cent stamps.
Finally, substituting the values in equation 2, where z = 2(x + y), we have:
z = 2(17 + 17)
z = 2(34)
z = 68.
Therefore, Jennifer bought 17 of the 8 cent stamps, 17 of the 10 cent stamps, and 68 of the 2 cent stamps.
20*8= 160, 20*10= 200, 40*2= 80, and 160+200+80= 240
therefore what Steve said was wrong