Create an abstract image showing a graph with two points on it. The graph should represent an unknown mathematical relationship between two variables, R and E. These two points represent the data points (R: 530, E: 16000) and (R: 730, E: 3600). The graph should not have any labels or numbers on its axes. The colors used in the image should be calming and appealing, with a balance between warmer and cooler hues.

R is partly constant and partly varies with E when R=530,E=16000 and when R=730,E=3600.

i)find the formula which connects R&E
i)find R when E=1300.

Good

Thanks a lot Reiny, you really helped me. God bless, it was totally helpful and was easy to understand.

R = mE + b

case1: R = 530, E = 16000
530 = 16000m + b **
case2: R = 730, E = 3600
730 = 3600m + b ***

subtract *** from **
-200 = 12400m
m = -1/62
back in ***
3600(-1/62) + b = 730
b = 24430/31

R = (-1/62)E + 24430/31

so when E = 1300
R = (-1/62) + 24230/31
= 23780/31 or appr 767

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fined R when E is = 1, 300

To find the formula that connects R and E, we can use the method of "direct variation.”

Direct variation is a relationship between two variables where one variable is a constant multiple of the other. In this case, we can assume that R varies directly with E, meaning R is proportional to E, and we can use the formula:

R = k * E

where k is the constant of variation.

To find the value of k, we can use the given values of R and E:

When R = 530 and E = 16000:
530 = k * 16000

Solving for k: k = 530 / 16000 = 0.033125

Now we have the value of k. The formula that connects R and E is:

R = 0.033125 * E

To find R when E = 1300, we can substitute the value of E into the formula:

R = 0.033125 * 1300

Calculating: R ≈ 43.06375

So, when E = 1300, R is approximately equal to 43.064.