A scale model of a building is 8 in. by 12 in. The scale is l in:15 ft. What are the dimensions of the actual building

well, if 1 inch ---> 15 ft

then 8 inches ---> 8(15) ft or 120 ft
and 12 inches ........

To find the dimensions of the actual building, we can use the scale given in the problem.

The scale is 1 inch to 15 feet.

By comparing the scale model dimensions to the actual dimensions, we can create a ratio:

(scale model dimension) / (actual dimension) = (scale) / (1)

Let's calculate the dimensions of the actual building:

For the width:

8 inches (scale model dimension) / x (actual dimension) = 1 inch (scale) / 15 feet

Cross-multiplying, we get:

8 inches * 15 feet = x (actual dimension) * 1 inch

120 inches = x (actual dimension)

So, the width of the actual building is 120 inches.

For the length:

12 inches (scale model dimension) / y (actual dimension) = 1 inch (scale) / 15 feet

Cross-multiplying, we get:

12 inches * 15 feet = y (actual dimension) * 1 inch

180 inches = y (actual dimension)

So, the length of the actual building is 180 inches.

Therefore, the dimensions of the actual building are 120 inches by 180 inches.

To find the dimensions of the actual building, we need to use the given scale and dimensions of the scale model.

First, let's identify the ratio that represents the scale. The scale is given as 1 in:15 ft, which means that every 1 inch on the scale model corresponds to 15 feet in real life.

Next, we need to use the dimensions of the scale model, which are 8 inches by 12 inches.

To find the length of the actual building, we can use the given ratio:

Length of actual building = Length of scale model × Scale ratio
= 8 inches × 15 feet/inch
= 120 feet

Similarly, to find the width of the actual building:

Width of actual building = Width of scale model × Scale ratio
= 12 inches × 15 feet/inch
= 180 feet

Therefore, the dimensions of the actual building are 120 feet by 180 feet.