2gm of a mixture of na2co3 and nahco3 on heating to a constant weight gave 224ml of co2 stp. Calculate the percentage of na2co3 in the mixture?
I don't understand anything
Please sand me solution
I will tell u
To calculate the percentage of Na2CO3 in the mixture, we need to follow a series of steps:
Step 1: Determine the molar mass of Na2CO3.
The molar mass of Na2CO3 can be calculated by adding the atomic masses of its constituent elements.
Molar mass of Na2CO3 = (2 * atomic mass of Na) + atomic mass of C + (3 * atomic mass of O)
The atomic masses of Na, C, and O are as follows:
Na: 22.99 g/mol
C: 12.01 g/mol
O: 16.00 g/mol
So, the molar mass of Na2CO3 = (2 * 22.99) + 12.01 + (3 * 16.00) = 105.99 g/mol (approximately)
Step 2: Determine the moles of CO2 formed.
Given that 224 mL of CO2 (at Standard Temperature and Pressure - STP) is produced, we can use the ideal gas law to determine the number of moles of CO2. At STP, 1 mole of gas occupies 22.4 L.
The volume of CO2 in liters is 224 mL / 1000 = 0.224 L
Using the ideal gas law, we can calculate the moles of CO2:
n(CO2) = V(CO2) / V(molar volume at STP)
n(CO2) = 0.224 L / 22.4 L/mol
n(CO2) = 0.01 moles
Step 3: Determine the moles of Na2CO3.
The reaction between Na2CO3 and HCl produces CO2 and can be balanced as follows:
Na2CO3 + 2HCl -> 2NaCl + H2O + CO2
From the balanced equation, we see that 1 mole of Na2CO3 reacts to produce 1 mole of CO2.
Therefore, the moles of Na2CO3 = moles of CO2 = 0.01 moles.
Step 4: Determine the mass of Na2CO3 in the mixture.
Using the formula: Mass = Moles × Molar mass
Mass of Na2CO3 = 0.01 moles × 105.99 g/mol = 1.06 g (approximately)
Step 5: Calculate the percentage of Na2CO3 in the mixture.
The percentage is calculated by dividing the mass of Na2CO3 by the total mass of the mixture and multiplying by 100.
Percentage of Na2CO3 = (Mass of Na2CO3 / Mass of mixture) × 100
Percentage of Na2CO3 = (1.06 g / 2 g) × 100 ≈ 53%
Therefore, the percentage of Na2CO3 in the mixture is approximately 53%.
Neat, you heated it to zero celcius to get gas.
YOu got .224/24 moles CO2.
in the 2g Na2CO3, you had available 2/molmassNa2CO3 moles of CO2.
The remainder of the moles of CO2 came from the bicarbonate. Calculate the moles of NaHCO3.
Now convert the mass of NaHCO3.
Knowing both original masses, you can easily determine the percent you need.