A liquid absorbs 45 kJ of heat, and its temperature increases from 305 K to 315 K. Determine the heat capacity of this liquid.
Cp = 45,000 J/delta T = ?
To determine the heat capacity of a substance, we need to use the equation:
Q = mcΔT
Where:
Q = Heat absorbed (in Joules)
m = Mass of the substance (in kg)
c = Specific heat capacity of the substance (in J/kg·K)
ΔT = Change in temperature (in K)
In this case, we don't have information about the mass of the liquid, so we can assume a mass of 1 kilogram for simplicity. Keep in mind that the specific heat capacity may vary depending on the substance.
Let's calculate the heat capacity of the liquid using the given information:
Q = 45 kJ = 45,000 J (converting kJ to J)
m = 1 kg (assume a mass of 1 kg)
ΔT = 315 K - 305 K = 10 K
Now, substitute the known values into the equation:
45,000 J = (1 kg) * c * 10 K
Simplifying the equation:
c = 45,000 J / (1 kg * 10 K)
c = 4,500 J/kg·K
Therefore, the heat capacity of this liquid is 4,500 J/kg·K.