The two equal sides of an isosceles triangle are 11 feet longer than the third side. The perimeter of this triangle is 56 feet. What is the length of the third (nonequal) side?
2(x+11)+x=56
solve for x
3x+22=56
x=(34/3)=11.33333 feet
x + 2(x+11) = 56
Hmm. You sure the perimeter is not 55?
thx @bobpursley
To solve this problem, we can set up an equation using the given information.
Let's say the length of the third side is x feet.
According to the problem, the two equal sides of the isosceles triangle are 11 feet longer than the third side. So, the length of each equal side is (x + 11) feet.
The perimeter of a triangle is the sum of the lengths of its sides. In this case, the perimeter is given as 56 feet. Therefore, we can set up the equation:
x + (x + 11) + (x + 11) = 56
Simplifying the equation, we have:
3x + 22 = 56
Subtracting 22 from both sides, we get:
3x = 34
Finally, dividing both sides by 3, we find:
x = 34/3
So, the length of the third (non-equal) side of the isosceles triangle is approximately 11.33 feet.