Please help and do it step by step all parts of questions and use:
T = time(s)
I=current (amps)
Q=net charge on object (Coulombs)
N=no electrons (and write if added or removed from object and how)
E=elementary charge
A piece of fuse wire has a diameter of 0.22mm and carries a current of 5.0A. There are 1.0 x 10^29 electrons per metre cubed. Calculate the mean drift velocity of the electrons in the wire.
velocitydrift=I/N*Area*chargeonelectron
I don't understand what it is that you don't understand. It is a simple formula. Convert current to amps, area to m^2, N to electcrons per cubic meter
To calculate the mean drift velocity of electrons in a wire, you can use the following formula:
Vd = I / (N * e * A)
Where:
Vd is the mean drift velocity of electrons
I is the current in the wire
N is the number of electrons per unit volume
e is the elementary charge
A is the cross-sectional area of the wire
Let's break down the steps to calculate the mean drift velocity:
Step 1: Convert the diameter of the wire to the cross-sectional area
The diameter of the wire is given as 0.22 mm. To calculate the cross-sectional area, we need to convert it to meters.
0.22 mm = 0.22 x 10^(-3) m (since 1 mm = 10^(-3) m)
Now, we can calculate the cross-sectional area using the formula for the area of a circle:
A = π * (d/2)^2
= π * (0.22 x 10^(-3) / 2)^2
Step 2: Calculate the number of electrons per unit volume
The number of electrons per unit volume is given as 1.0 x 10^29 electrons per meter cubed.
N = 1.0 x 10^29 electrons/m^3
Step 3: Calculate the mean drift velocity
Now, we can substitute the values into the formula for mean drift velocity:
Vd = I / (N * e * A)
= 5.0A / (1.0 x 10^29 e^-/m^3 * 1.6 x 10^(-19) C * A)
Note: The elementary charge, e, is approximately 1.6 x 10^(-19) Coulombs.
Step 4: Calculate the mean drift velocity
Substitute the values from the given information into the formula:
Vd = 5.0A / (1.0 x 10^29 e^-/m^3 * 1.6 x 10^(-19) C * A)
Now, we can simplify the equation by canceling out units:
Vd = 5.0A / (1.0 x 10^29 * 1.6 x 10^(-19))
Finally, calculate the mean drift velocity:
Vd ≈ 3.13 x 10^10 m/s (approximately)
Therefore, the mean drift velocity of the electrons in the wire is approximately 3.13 x 10^10 m/s.