Identify the center and radius of a circle with equation (x+4) 2 + (y-2) 2 = 36

you should have seen in your text that the circle with center at (h,k) and radius r is

(x-h)^2 + (y-k)^2 = r^2

Just plug in your numbers.

To identify the center and radius of a circle given its equation, we can compare the given equation to the standard equation of a circle, which is:

(x - h)^2 + (y - k)^2 = r^2

In the given equation, (x+4)^2 + (y-2)^2 = 36, we can observe that the expressions (x+4)^2 and (y-2)^2 represent the squared distance between the coordinates (x, y) and the points (-4, 2) respectively. And 36 represents the radius squared (r^2).

By comparing the given equation to the standard form, we can determine that the center of the circle is (-4, 2) and the radius is the square root of 36, which is 6.