Calculate the pH at which free phenobarbital(an acid) will precipitate from a solution contain 0.0394M(Cs) sodium phenobarbital. Given: molar mass of phenobarbital=232 g/mol; Ka=3.9x10^-8; and water soluble of free phenobarbital(Co)=1g in 1000ml.

Thank you all of you!!!!!:)

I don't understand the question. What's Cs? What's Co. That last portion of ";and water soluble of free phenobarbital(Co) = 1 in 1000 mL" doesn't make sense to me.