Each number cube has 6 faces numbered 1-6. John tossed 2 number cubes several times and

added the numbers each time. Sum of the number of cubes

total tally number of times
2 1 ?
7 4 ?

always 2 cubes

I assume you meant to count the number of times each sum comes up. I have no idea how many times they were tossed, or what were the results...

To find the missing values in the tally and number of times, you can look at the given information and use deductive reasoning.

In the provided information, it states that John tossed 2 number cubes several times and added the numbers each time. Based on this, we can infer that the sum of the two number cubes can range from a minimum of 2 (if both cubes show a 1) to a maximum of 12 (if both cubes show a 6).

Looking at the given data, we can see that the total is the sum of the numbers on the two cubes, the tally represents how many times that specific sum appears, and the number of times refers to the frequency of different sums.

According to the information given:
- The total is 2, and it appears once.
- The total is 7, and it appears four times.

Now, we can fill in the missing values in the tally and number of times:

total tally number of times
2 1 1
7 4 4

Therefore, the number of times the sum 2 appears is 1, and the number of times the sum 7 appears is 4.

To find the missing values in the tally and number of times, we can analyze the information given.

The total sum of the two number cubes comes from adding the numbers on each face of the cubes. Each number cube has 6 faces numbered from 1 to 6, so the possible outcomes for each cube are 1, 2, 3, 4, 5, and 6.

From the given table, we have two rows: one with a total of 2 and a tally of 1, and another with a total of 7 and a tally of 4.

Let's start with the row where the total sum is 2 and the tally is 1. This means that there was only one occasion where the sum of the two number cubes equaled 2. Since the smallest outcome of rolling two number cubes is 1+1 = 2, it indicates that the outcome must be 1+1 = 2. Therefore, the number of times this occurred is 1.

Moving to the second row, where the total sum is 7 and the tally is 4. To get a sum of 7, we can have the following combinations: 1+6, 2+5, 3+4, 4+3, 5+2, and 6+1. Each combination adds up to 7. Since the tally is 4, it suggests that there were four occasions where the sum of the number cubes equaled 7. Hence, the number of times this occurred is 4.

In summary:
- For a total sum of 2, the number of times is 1.
- For a total sum of 7, the number of times is 4.