A parallelogram has vertices at A(-2,-1), B(-2,1), C(1,2),and D(1,0). If it is translated 1 unit right and 1 unit up, what are the vertices of the image?
How easy is that?
add 1 to the x value and add 1 to the y value.
I will do the first, you do the rest.
A(-2,-1) -----> A1(-1, 0)
To find the vertices of the image after a translation of 1 unit right and 1 unit up, you need to add 1 to the x-coordinate and 1 to the y-coordinate of each vertex of the parallelogram.
Given the original coordinates of the parallelogram's vertices:
A(-2,-1), B(-2,1), C(1,2), and D(1,0)
Add 1 to the x-coordinate of each vertex to translate 1 unit right:
A(-2 + 1, -1), B(-2 + 1, 1), C(1 + 1, 2), and D(1 + 1, 0)
Simplifying the coordinates gives:
A(-1,-1), B(-1,1), C(2,2), and D(2,0)
Now, add 1 to the y-coordinate of each vertex to translate 1 unit up:
A(-1, -1 + 1), B(-1, 1 + 1), C(2, 2 + 1), and D(2, 0 + 1)
Simplifying the coordinates gives the vertices of the image:
A(-1, 0), B(-1, 2), C(2, 3), and D(2, 1)
Therefore, the vertices of the image after the translation are A(-1, 0), B(-1, 2), C(2, 3), and D(2, 1).