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Chemistry

The Ka of HClO is 3.0x 10^-8 at 25°c. What is the percent ionization of HClO in a 0.015M aqueous solution of HCLO at 25°c?

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  1. ............HClO ==> H^+ + ClO^-
    I..........0.015.....0......0
    C...........-x.......x......x
    E.........0.015-x....x......x

    Ka = (H^+)(ClO^-)/(HClO)
    Plug in the E line into Ka expession, solve for x, then %ionization = [(x)/0.015]*100 = ?

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  2. 0.14

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  3. percent ionization=concentration of ionized acid/initial concentration of acid*100
    [H3O+]equil/HA]init*100%

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