how many mL of .122 M MnO4- are required to react with an excess of C2O42- in order to produce 75.25mL of carbon dioxide gas measured at 30 degree C and 715 torr?

2[MnO4]^- + 5[C2O4]^2-+ H^+ ==> 2Mn^2+ + 10-CO2 + etc.

I balanced only the redox pat.
Use PV = nRT and calculate n = number of mols.
mols CO2 needed x (2 mol MnO4/10 mols CO2)= mols KMnO4 needed.
Then M = mols/L. ou know M KMnO4 and mols KMnO4. Solve for L and convert to mL. Post your work if you get stuck.

To determine the number of mL of 0.122 M MnO4- required to react with an excess of C2O42- to produce 75.25 mL of carbon dioxide gas at 30 degrees Celsius and 715 torr, we need to use stoichiometry.

The balanced chemical equation for the reaction between MnO4- and C2O42- is as follows:

2 MnO4- + 5 C2O42- + 16 H+ -> 2 Mn2+ + 10 CO2 + 8 H2O

From the balanced equation, we can see that the stoichiometric ratio between MnO4- and CO2 is 2:10.

Given:
Volume of CO2 gas = 75.25 mL
Temperature = 30 degrees Celsius
Pressure = 715 torr

Step 1: Convert temperature to Kelvin
To convert Celsius to Kelvin, use the following formula:
K = °C + 273.15

T(K) = 30°C + 273.15
T(K) = 303.15 K

Step 2: Convert pressure to atm
To convert torr to atm, use the following conversion:
1 atm = 760 torr

Pressure(atm) = 715 torr / 760 torr/atm
Pressure(atm) = 0.9418 atm

Step 3: Convert volume of CO2 to moles
To convert volume to moles, use the ideal gas law equation:
PV = nRT

n = PV / RT

n = (0.9418 atm) * (75.25 mL) / [(0.0821 L * atm/(mol * K)) * (303.15 K)]
n ≈ 0.0239 mol

Step 4: Determine the number of moles of MnO4- needed
From the balanced equation, we know that the stoichiometric ratio between MnO4- and CO2 is 2:10.

Therefore, the number of moles of MnO4- needed is:

moles of MnO4- = (2 mol/10 mol) * 0.0239 mol
moles of MnO4- ≈ 0.00478 mol

Step 5: Calculate the volume of 0.122 M MnO4- needed
The given concentration is 0.122 M, meaning there are 0.122 moles of MnO4- per liter of solution.

volume of MnO4- = (0.00478 mol) / (0.122 mol/L)
volume of MnO4- ≈ 0.0392 L

Step 6: Convert volume to mL
To convert liters to milliliters, multiply by 1000:

volume of MnO4- = 0.0392 L * 1000 mL/L
volume of MnO4- ≈ 39.2 mL

Therefore, approximately 39.2 mL of 0.122 M MnO4- is required to react with an excess of C2O42- to produce 75.25 mL of carbon dioxide gas measured at 30 degrees Celsius and 715 torr.

To determine the amount of MnO4- required to react with C2O42-, we need to follow these steps:

Step 1: Write and balance the balanced chemical equation for the reaction.

The balanced equation for the reaction between MnO4- and C2O42- is:

2MnO4- + 5C2O42- + 16H+ → 2Mn2+ + 10CO2 + 8H2O

Step 2: Calculate the number of moles of CO2 produced.

To calculate the number of moles of CO2, we can use the ideal gas law equation:

PV = nRT

Where:
P = Pressure of the gas (715 torr)
V = Volume of the gas (75.25 mL)
n = Number of moles of gas
R = Ideal gas constant (0.0821 L·atm/mol·K)
T = Temperature in Kelvin (30 °C + 273.15 = 303.15 K)

First, convert the volume from milliliters to liters:
75.25 mL ÷ 1000 = 0.07525 L

Now, calculate the number of moles of CO2 using the ideal gas law equation:

n = (PV) / (RT)
n = (715 torr * 0.07525 L) / (0.0821 L·atm/mol·K * 303.15 K)

Step 3: Determine the stoichiometry between CO2 and MnO4-.

From the balanced equation, we know that 2 moles of MnO4- react with 10 moles of CO2.

Step 4: Calculate the number of moles of MnO4- needed.

Since the stoichiometry ratio between MnO4- and CO2 is 2:10, we can set up a ratio to find the number of moles of MnO4-:

2 moles MnO4- / 10 moles CO2 = x moles MnO4- / n moles CO2

Substitute the value of n from Step 2:

2 / 10 = x / n
x = (2/10) * n

Step 5: Calculate the volume of the 0.122 M MnO4- solution required.

To convert the moles of MnO4- to volume, we can use the molarity equation:

Molarity (M) = moles / volume (L)

Rearrange the equation to solve for volume:

Volume (L) = moles / Molarity

Volume (L) = [(2/10) * n] / 0.122 M

Step 6: Calculate the volume in milliliters.

Multiply the volume in liters by 1000 to convert it to milliliters:

Volume (mL) = Volume (L) * 1000

Now, you can substitute the calculated values from Steps 2 and 6 into the equation to find the volume of the 0.122 M MnO4- solution required.