Physics

A pipe has a cross sectional radius of 6.00 cm and is carrying water moving at .380 m/sec. If the pipe narrows to a radius of 3.50 cm, what will be the speed of the water in the narrow segment? What is the flow rate in each segment?

thank you!!!!!!!

asked by Anon

  1. lAW OF CONTINUITY:

    area1*speed1=area2*speed2
    speednarrow=PI(6^2)*.380/(.350^2)

    volume flow rate=speed*area do that for both sides.

    posted by bobpursley
  2. oops, add a PI in the denominator of the law of continuity, area=pI*radius^2

    posted by bobpursley

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