physics

What is the average useful power output of a person who does 5.50×106 J of useful work in 6.50 h?

235 W correct answer

Working at this rate, how long will it take this person to lift 1850 kg of bricks 1.20 m to a platform? (Work done to lift his body can be omitted because it is not considered useful output here.)

92.6 s correct

can someone give me the steps to achieve these answers?

asked by stephanie
  1. 6.5 h * 3600 s/h = 23400 seconds
    so
    5.5 * 10^6/2.34*10^4 watts

    work done = m g h = 1850*9.81*1.2
    power = work/time
    235 = work/time
    so
    time = work/235

    posted by Damon

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