As Physics

Use the equations below:
P=mv
Ek=1/2mv^2
2) A linear air track can be used to investigate collisions. Two trolleys or “gliders� are supported on a cushion of air. A glider of mass 0.30kg is stationary in the middle of the track. A second glider of mass 0.25kg and velocity of 0.20ms-1 collides with the first glider and they stick together.
You may assume that this collision is perfectly elastic.
A) What is meant by a “perfectly elastic� collision?
B) Calculate the velocity of the glider combination immediately after the collision.

6 marks


please help with B

its 0.25 x 0.2+ 0.3 x 0 = (0.25+0.3)V as one of the trolley is 0.3kg so am i right?

bef=0.05
aft=0.55v
so 0.05=0.55v
0.05/0.55= 0.0909..

am i right

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asked by cake
  1. If they stick together the collision is NOT perfectly elastic. Energy is lost as heat.

    You did the velocity stuck together correctly.

    If it were perfectly elastic then it is a whole different ball game.

    momentum before = momentum after
    0.05 = .25 V2 + .3 V1
    enerrgy before = energy after
    (1/2)(.25)(.2^2) = (1/2).25 V2^2 + (1/2).3 V1^2

    posted by Damon
  2. so it is elastic collision, the momentum before and after is same and i dont think you need tow ok out energy

    posted by cake

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