chemistry

determine the number of grams of Ne gas that must be added to a container in order for the volume to increase to 38.2 L at constant pressure and temperature if the container had an initial volume of 25.0 L and 2.0 moles of Ne

asked by j
  1. The shorter way to work this is harder to explain so let me show you the long way. First assume a value for T, use PV = nRT, and solve for P.
    P = ?
    V = 25.0L
    n = 2 mols (we'll call this n1)
    R -= 0.08206
    T = 273.

    After you get P, use PV = nRT again. Use the same valus for R, T, and the value you obtained for P. Solve for n = how many mols must be in the container. Call that n2.
    So how many mols Ne must be added. That's n2-n2 = ? and convert to grams. g = mols x molar mass.

    posted by DrBob222
  2. 1.72

    posted by chris

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