If m ∇ n = (m2 - n) ÷ n for all real numbers m and n, where n ≠ 0, what is the value of 6 ∇ 3?

huh? Just plug in your numbers:

m∇n = (m2-n) ÷ n
so
6∇3 = (6^2-3)/3 = 11

Thx

To find the value of 6 ∇ 3 using the given function m ∇ n = (m^2 - n) ÷ n, we substitute m = 6 and n = 3 into the function:

6 ∇ 3 = (6^2 - 3) ÷ 3

Now we simplify this expression:

6^2 = 6 * 6 = 36
36 - 3 = 33

The expression becomes:

33 ÷ 3

Calculating the division:

33 ÷ 3 = 11

Therefore, the value of 6 ∇ 3 is 11.