If m ∇ n = (m2 - n) ÷ n for all real numbers m and n, where n ≠ 0, what is the value of 6 ∇ 3?
huh? Just plug in your numbers:
m∇n = (m2-n) ÷ n
so
6∇3 = (6^2-3)/3 = 11
Thx
To find the value of 6 ∇ 3 using the given function m ∇ n = (m^2 - n) ÷ n, we substitute m = 6 and n = 3 into the function:
6 ∇ 3 = (6^2 - 3) ÷ 3
Now we simplify this expression:
6^2 = 6 * 6 = 36
36 - 3 = 33
The expression becomes:
33 ÷ 3
Calculating the division:
33 ÷ 3 = 11
Therefore, the value of 6 ∇ 3 is 11.