The ratio of the strings that plays the notes F and G is 9 to 8.if a string 32 cm long plays G, what is the length of the string that plays an F?
G is 32 = 8*4, so
F is 9*4 = 36
To find the length of the string that plays an F note, you can use the given ratio.
The ratio of the strings that play the notes F and G is 9 to 8. This means that for every 9 units of length on the string that plays F, there are 8 units of length on the string that plays G.
Let's assume the length of the string that plays F is x cm. According to the ratio, we can set up the following proportion:
9/8 = x/32
To solve for x, we can cross multiply:
9 * 32 = 8 * x
288 = 8x
Divide both sides of the equation by 8:
288/8 = x
36 = x
Therefore, the length of the string that plays an F note is 36 cm.
To find the length of the string that plays an F note, we'll use the given ratio of 9 to 8 and the length of the string that plays a G note (32 cm).
Let's set up a proportion to solve for the length of the string that plays an F note:
Length of string playing F / Length of string playing G = Ratio of F to G
Let's plug in the values we know:
Length of string playing F / 32 cm = 9/8
To isolate the length of the string playing F, we can cross-multiply:
Length of string playing F = (9/8) * 32 cm
Now, let's simplify the expression:
Length of string playing F = (9 * 32 cm) / 8
Multiplying numerator and denominator:
Length of string playing F = 288 cm / 8
Simplifying further:
Length of string playing F = 36 cm
Therefore, the length of the string that plays an F note is 36 cm.