Draw a speed v against time graph by guessing of the values of your trip to school this morning. show how this graph can be used to determine distance

Draw a speed v against time graph by guessing of the values of your trip to school this morning. show how this graph can be used to determine distance

the area under the curve is the distancee

5. Draw a speedv against time graph by guessingof the values of your

trip to school this morning. Show how this graph can be used to
determine distance.

I don't no so i want it

Yes

To draw a speed vs. time graph, we need to make educated guesses about the values of your trip to school this morning. Let's assume that your trip took 30 minutes and you traveled at a relatively constant speed. We can divide the trip into equal time intervals and assign corresponding speed values to each interval.

For example, let's assume you traveled at a speed of 20 km/h for the first 10 minutes, then increased your speed to 30 km/h for the next 10 minutes, and finally reduced your speed to 10 km/h for the final 10 minutes of the trip.

Now, we can plot these speed values on the vertical (y) axis and the corresponding time intervals on the horizontal (x) axis. Each speed value will be plotted at the midpoint of its respective time interval.

The resulting speed vs. time graph will show a line connecting the three data points: (10 min, 20 km/h), (20 min, 30 km/h), and (30 min, 10 km/h).

To determine distance from this graph, we need to recall the definition of speed – it is the rate at which distance is covered per unit of time. In mathematical terms, speed = distance / time.

If we rearrange this equation to isolate distance, we get distance = speed x time. So, by multiplying the speed at a particular time interval by the corresponding time interval, we can calculate the distance covered during that time.

For example, to determine the distance covered in the first 10 minutes, we can calculate:
Distance = (20 km/h) x (10 min/60 min) = 3.33 km.

Similarly, for the second 10 minutes:
Distance = (30 km/h) x (10 min/60 min) = 5 km.

Lastly, for the final 10 minutes:
Distance = (10 km/h) x (10 min/60 min) = 1.67 km.

By summing up these distances, we get the total distance covered during your trip to school this morning: 3.33 km + 5 km + 1.67 km = 10 km.