# algebra

A perfume maker wishes to blend perfume valued at \$ 410 an ounce with perfume worth \$ 250 an ounce to obtain a mixture of 40 ounce worth \$ 300 an ounce. How much of the \$ 410 perfume should he use?

1. If you take the amount of \$410 perfume to be used as x ounces, the amount of \$250 perfume to be used becomes (40-x) ounces.

For the final mixture to be worth \$300 an ounce:

410x + 250(40-x) = 300(40)

Solve for x

posted by Arora

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