limit x tends to infinity ( 1+root n)/(1-rootn)

asked by Binoy kumar mahato
  1. You must have meant:
    lim (1 + √n)/(1-√n) as n ---->∞
    divide top and bottom my √n
    = lim (1/√n + 1)/(1/√n - 1) as n ---->∞

    Now look at the 1/√n term
    as as n ---->∞ , 1/√n -----> 0
    e.g. let n = 10,000,000 , 1/√10,000,000 = .00031... getting small

    So you are left with
    lim (0 + 1)/(0 - 1) as n ---->∞
    = -1

    posted by Reiny

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