The cylindrical tank has a radius of 5 feet and is 2/3 full of water. To the nearest cubic foot, how many cubic feet of water are in the tank?
In order to find the volume of the cylinder, you also require its height.
To find the volume of water in the cylindrical tank, we need to use the formula for the volume of a cylinder: V = π * r^2 * h, where V represents the volume, π is a mathematical constant approximately equal to 3.14, r is the radius of the cylinder, and h is the height of the water in the cylinder.
In this case, the radius of the cylindrical tank is given as 5 feet. To calculate the height of the water, we need to determine what fraction of the tank is filled, which is given as 2/3 or two-thirds.
Since the tank is cylindrical, we can assume that the filled portion forms a cylindrical shape as well.
To calculate the height of the filled water in the tank, we can multiply the total height of the tank by the fraction of the tank that is filled. The total height is not provided in the question, so we will assume it is the same height as the diameter of the cylinder, which is twice the radius (10 feet).
Therefore, the height of the water in the tank is (2/3) * 10 feet = 20/3 feet.
We can now substitute the values into the volume formula and calculate the volume of water in the tank.
V = π * r^2 * h
V ≈ 3.14 * 5^2 * (20/3)
V ≈ 3.14 * 25 * (20/3)
V = 523.33 cubic feet (rounded to nearest cubic foot)
Therefore, to the nearest cubic foot, there are approximately 523 cubic feet of water in the tank.