math

A bag contains some silver balls and golden balls. If you remove one silver ball from the bag, 1/7 of the remaining balls in the bag are silver. If you remove 2 golden balls from the bag, then 1/5 of the remaining balls in the bag are silver. How many balls are there in the bag at first?

asked by lala
  1. s + g in bag at first

    s-1 = (1/7)(s+g-1)

    s = (1/5)(s+g-2)

    posted by damon

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