What is the maximum amount of water (in grams) that can be produced given 4 moles of hydrogen and 4 moles of oxygen?
2H2+O2>>>2H2O
four moles of H2 produces 4moles water
4moles water=4*18grams water
you need 2 mols of H2 for every mol of O2
2 H2 + O2 -> 2 H2O
or in this problem
4H2 + 2 O2 --> 4 H2O
H2 is 2+16 = 18 grams/mol
so
4 * 18 grams
To calculate the maximum amount of water that can be produced, you'll need to use the balanced equation for the formation of water from hydrogen and oxygen:
2H₂ + O₂ → 2H₂O
From the balanced equation, we can see that 2 moles of hydrogen react with 1 mole of oxygen to produce 2 moles of water. Therefore, 4 moles of hydrogen will react with 2 moles of oxygen to produce 4 moles of water.
To find the maximum amount of water in grams, you'll need to know the molar mass of water. The molar mass of water (H₂O) is approximately 18 grams per mole.
So, multiplying the number of moles of water (4 moles) by the molar mass of water (18 grams/mole), we can calculate the maximum amount of water that can be produced:
4 moles × 18 grams/mole = 72 grams
Therefore, the maximum amount of water that can be produced from 4 moles of hydrogen and 4 moles of oxygen is 72 grams.