How can you determine if a polynomial is the difference of two squares? I think that if the polynomial is x^2-64 that this is a polynomial that is a difference of two squares because if you factor it out you would get (x+8)(x-8).
In algebra special products and the questions says to factor the equation 200x^2-18 and I don't get how to. factor out a two, then what remains will be the difference between two perfect squares. I got as far as this 2(100x-3)^2
5y^8-125 *you have to factor completley easy. Take out the five: 5(y^8-25) Now, isnt y8 the same as y4 )2 ? That is a square, so you have that y4 squared minus another perfect square? That factor as the difference of two squares.
How many perfect squares are less than or equal to 36? how many less than or equal to 144? In general how many perfect squares are less than or equal to n^2? Using all these answers, estimate the number of perfect squares less
the integer 49 can be written as the sum of smaller perfect squares in a variety of ways. one such way includes six terms: 25+9+4+1+1. if each term has a value between 0 and 49,what is the fewest number of perfect square terms
the only perfect number of the form x(n) + y(n) A perfect number is an integer that is equal to the sum of its positive divisors (not including itself). Therefore, 6 is a perfect number, since its positive divisors are 1, 2, and 3