Question

A particle starts at x=0 and moves along the x-axis with velocity v(t)=2t+1 for time t is less than or equal to 0. Where is the particle at t=4?

Answer 1

I assume you are in calculus.

Postition=INTEGRAL v(t) dt=INT (2t+1)dt
= t^2 + t

Put in t=4 and compute.

Answer 2

so my answer would basically be 20

Answer 3

not basically 20, it is 20. Units were not specified.

Answer 4

oh okay Thank You

Answer 5

the question makes no sense. It starts at time zero, and there is no definition of velocity after that.

Answer 6

so t less than or equal to 0 is invaild

Answer 7

I copied the problem out of my textbook

Answer 8

The problem asks for postion at time 4, which is outside the time given for the velocity expression, if you typed it correcty. One needs the velocity function for time zero to somewhat beyond 4 to calculate postion.

Answer 9

the velocity v(t)= 2t + 1

Answer 10

barbara, you originally asked for position at time 4 for a function that has a certain velocity function before time zero. One cant calculate postition for time 4 unless there is some indication of what it was doing between time zero and time 4.