Calculate the volume of 1.86M Na3PO4 solution that can be prepared from 5.45 g of Na3PO4
To calculate the volume of a solution, we need to use the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
First, we need to calculate the moles of Na3PO4 using the given mass of 5.45 g:
Molar mass of Na3PO4 = (22.99 * 3) + (15.999 * 4) = 163.94 g/mol (approximately)
moles = mass / molar mass = 5.45 g / 163.94 g/mol = 0.0332 mol (approximately)
Now that we have the moles of Na3PO4, we can use the molarity to find the volume of the solution. The molarity is given as 1.86 M, which means 1.86 moles of Na3PO4 per liter of solution.
Molarity = moles of solute / volume of solution
Rearranging the formula to solve for volume:
Volume of solution = moles of solute / Molarity
Volume of solution = 0.0332 mol / 1.86 M = 0.0179 L (approximately)
Therefore, the volume of the 1.86 M Na3PO4 solution that can be prepared from 5.45 g of Na3PO4 is approximately 0.0179 liters (or 17.9 ml).
Moles of Na3PO4 = 5.45 g/molar mass of Na3PO4 g/mol
Let the volume of the Na3PO4 solution be=v dm^3
1.86 mol/dm^3 * v dm^3 = moles of Na3PO4
Hope this helps..