The ferris wheel at the town fair has a radius of 25 feet. Passengers enter the cars on the ferris wheel at it’s lowest point which is 10 feet off the ground. Assume that passengers rotate on the wheel 5 times in 1 minute. What is the highest point off the ground that a passenger will be when riding the ferris wheel?
10+2*25 = 60
Where did 2 come from
the wheel's diameter is twice the radius...
so it has be twice as big wich means that you have to times it by 2 my maths teacher 2 years ago mr beaker taught me that.
To determine the highest point off the ground that a passenger will reach on the Ferris wheel, we need to find the maximum height of an object moving in a circle.
The Ferris wheel is essentially a rotating circle, and the highest point will be at the topmost position on this circle.
To find the highest point, we can use the concept of the circumference and the radius of the circle.
The formula for the circumference of a circle is: C = 2πr, where C is the circumference and r is the radius.
In this case, the radius of the Ferris wheel is given as 25 feet. So, we can find the circumference as follows: C = 2π(25) = 50π feet.
Since passengers rotate on the wheel 5 times in 1 minute, we need to divide the circumference by the number of rotations to determine the distance covered in one rotation.
The distance covered in one rotation is: 50π / 5 = 10π feet.
Now, to find the highest point off the ground, we need to add the height off the ground at the lowest point to the radius of the Ferris wheel.
The height off the ground at the lowest point is given as 10 feet, and the radius is 25 feet.
Therefore, the highest point off the ground will be: 10 + 25 = 35 feet.
So, when riding the Ferris wheel, the passengers will reach a maximum height of 35 feet off the ground.