The area of a rectangle is 35
square meter. The width is 25
meter.
a. What is the length of the rectangle? Write your answer as a fraction in simplest form.
The length of the rectangle is 1
1
2 meters.
b. How many times greater is the length than the width? Write your answer in simplest form.
The length is times greater than the width.
A = LW
35 = 25L
35/25 = L
1 2/5 = L
To find the length of the rectangle, we can use the formula for the area of a rectangle:
Area = Length * Width
Given that the area of the rectangle is 35 square meters and the width is 25 meters, we can rearrange the formula to solve for the length:
Length = Area / Width
Plugging in the values, we have:
Length = 35 sq. meters / 25 meters
Simplifying the fraction:
Length = 7/5 meters
So, the length of the rectangle is 7/5 meters.
To find how many times greater the length is than the width, we can divide the length by the width:
Times greater = Length / Width
Plugging in the values, we have:
Times greater = (7/5) meters / 25 meters
Simplifying the fraction:
Times greater = 7/125
Therefore, the length is 7/125 times greater than the width.