A 1,100 kg car is traveling at 15 m/s when the brakes are suddenly applied. How far a distance will it travel if the brakes can exert a force of 6,000 N?

F = m a

braking so -
-6000 = 1100 a
a = -5.45 m/s^2

v = Vi + a t
at stop
0 = 15 -5.45 t
t = 2.75 seconds to stop

average speed during stop = 15/2 = 7.5 m/s

d = 7.5 * 2.75 = 20.6 meters

Not sure where that 0.92 came from, now why it didn't trigger a sanity check.

Go with Damon, as usual.

Well, well, well, looks like we've got ourselves a physics problem! Now let's put on our thinking caps and solve this!

First, we need to find the deceleration of the car. To do that, we'll use Newton's second law: force equals mass times acceleration. Rearranging that equation, we get acceleration equals force divided by mass.

So, for our car, the acceleration will be 6,000 N divided by 1,100 kg. Now, don't expect me to do the math. I'm a clown, not a calculator. But I'm sure you can handle dividing those numbers!

Once we have the acceleration, we can use the equation of motion to find the distance traveled. The equation is: distance equals initial velocity squared divided by twice the acceleration.

So, plug in the values you know – the initial velocity of 15 m/s and the acceleration you just calculated – and you'll have your answer. Just remember to give the distance in meters, not in laughs!

To calculate the distance the car will travel when the brakes are applied, we can use the equation for the force of friction:

Force of friction = mass * acceleration

In this case, the force of friction is equal to the force applied by the brakes, which is 6,000 N. The mass of the car is 1,100 kg. We need to find the acceleration.

The equation for acceleration is:

acceleration = (final velocity - initial velocity) / time

Since the car is coming to a stop, the final velocity is 0 m/s. The initial velocity is given as 15 m/s. We need to find the time it takes for the car to come to a stop.

The equation for time is:

time = (final velocity - initial velocity) / acceleration

Since the final velocity is 0 m/s, the equation simplifies to:

time = -initial velocity / acceleration

Now we can substitute the values we know into the equations to find the distance traveled.

First, let's calculate the acceleration:

acceleration = force of friction / mass
acceleration = 6,000 N / 1,100 kg

acceleration ≈ 5.45 m/s²

Next, let's calculate the time:

time = -initial velocity / acceleration
time = -15 m/s / 5.45 m/s²

time ≈ -2.75 s

The time is negative because we are dealing with deceleration.

Finally, to find the distance traveled, we can use the equation:

distance = initial velocity * time + (1/2) * acceleration * time²

distance = 15 m/s * -2.75 s + (1/2) * 5.45 m/s² * (-2.75 s)²

distance ≈ -41.25 m

Since distance cannot be negative, we can take the absolute value to find the positive distance:

distance ≈ 41.25 m

Therefore, the car will travel approximately 41.25 meters before coming to a stop when the brakes are suddenly applied.

F=ma, so a = -5.45 m/s^2

15+at=0 so t = 0.92 s

s(t) = 15t+ 1/2 at^2
= 15*0.92 - 5.45/2 * 0.92^2 = 11.49 m