Calculate the molar enthalpy of reaction per mole of carbon in the following reaction:
3 C(s) + 2 Fe2O3(s) + 466 kJ c12-u3_files/i0210000.jpg 4 Fe(s) + 3 CO2(g)
a.
+466 kJ/mol C
b.
+155 kJ/mol C
c.
+117 kJ/mol C
d.
–466 kJ/mol C
e.
–155 kJ/mol C
I don't know what the link is but dH rxn = (n*dHo products)-(n*dHo proucts)
Then divide by 3 to get per mols C.
To calculate the molar enthalpy of reaction per mole of carbon, we need to determine the number of moles of carbon involved in the reaction. We can do this by looking at the balanced equation.
According to the balanced equation, we have 3 moles of carbon (C) reacting with 2 moles of Fe2O3 to produce 4 moles of Fe and 3 moles of CO2.
To calculate the molar enthalpy of reaction per mole of carbon, we divide the given enthalpy change (466 kJ) by the number of moles of carbon (3 moles):
466 kJ / 3 moles = 155.33 kJ/mol C
Therefore, the correct answer is b. 155 kJ/mol C.
To calculate the molar enthalpy of reaction per mole of carbon, we first need to calculate the number of moles of carbon involved in the reaction.
From the balanced chemical equation, we can see that the coefficient of carbon (C) is 3. This means that 3 moles of carbon are involved in the reaction.
Next, we need to calculate the molar enthalpy of reaction. The given equation shows that the reaction releases 466 kJ of energy.
To find the molar enthalpy of reaction per mole of carbon, we divide the energy change by the number of moles of carbon:
Molar enthalpy of reaction per mole of carbon = (Energy change) / (Number of moles of carbon)
= 466 kJ / 3 mol
= 155.33 kJ/mol C
Rounding to the appropriate number of significant figures, the molar enthalpy of reaction per mole of carbon is +155 kJ/mol C.
Therefore, the correct option is b. +155 kJ/mol C.