Calculate the total number of electrons that are lost in 1.00 g samples of fructose and oleate. (Note: the number of electrons lost per carbon atom is equivalent to its increase in oxidation state.)
No. e- lost in 1.00 g fructose = _______________
No. e- lost in 1.00 g oleate = _______________
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NA = 6.022 x 1023 mol-1 1 Cal (kcal) = 4.184 kJ
The carbons in each molecule are being oxidized to carbon dioxide in aerobic respiration.
To calculate the total number of electrons lost in 1.00 g samples of fructose and oleate, we need to determine the number of carbon atoms in each compound and then calculate the oxidation state change for each carbon atom.
1. Fructose: C6H12O6
Fructose has 6 carbon atoms. We need to determine the change in oxidation state for each carbon atom when it undergoes a reaction that leads to the loss of electrons.
The basic oxidation state for carbon in organic compounds is +4 (since it has four valence electrons). If the oxidation state increases, it means that electrons are lost.
Fructose consists of six carbon atoms, so the total number of electrons lost in 1.00 g of fructose can be calculated as follows:
No. e- lost in 1.00 g fructose = (6 carbon atoms) x (oxidation state change) x (Avogadro's number)
= (6 carbon atoms) x (change in oxidation state) x (6.022 x 10^23 mol^-1)
To calculate the change in oxidation state, we need to know the specific reaction or process that occurs in fructose. Without this information, we cannot determine the exact oxidation state change.
2. Oleate: C18H34O2
Oleate has 18 carbon atoms, similar to fructose. We can follow the same procedure to calculate the total number of electrons lost in 1.00 g of oleate.
No. e- lost in 1.00 g oleate = (18 carbon atoms) x (oxidation state change) x (Avogadro's number)
= (18 carbon atoms) x (change in oxidation state) x (6.022 x 10^23 mol^-1)
Again, the actual change in oxidation state depends on the specific reaction or process involving oleate, which we don't have in this question.
In summary, to calculate the total number of electrons lost in 1.00 g samples of fructose and oleate, we need to know the change in oxidation state for each carbon atom, which requires information about the reaction or process involved in each compound. Without this information, we cannot calculate the exact values.