physics

A ball is launched at a velocity of 20 m/s in a direction making an angle of 25° upward with the horizontal.  i) calculate  maximum height reached by the object                                                                           ii) Calculate the total flight time of the object                                                                                    iii) Calculate  the horizontal range (maximum x above ground) of the object 

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  1. horizontal
    U = 20 cos 25 for the whole trip
    so
    range = 20 cos 25 * time in air

    vertical
    initial speed up = Vi = 20 sin 25
    v = Vi - g t where t is time up
    so
    t = Vi/g = (20/9.8) sin 25

    time down = t = time up
    so
    time in air = 2 t
    so
    range = 2 t * 20 cos 25

    for max height, height at t
    h = Vi t - 4.9 t^2

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