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How many centavos are equal to P2.50?
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we already went through this, don't you remember? You even got it right!
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robert has 50 coins.there are 5 centavos and 10centavos total of 3.50.. How many 5 centavos are there?
Top answer:
5x + 10(50-x) = 350
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how many centavos are equal to P2.50
Top answer:
no idea. How many centavos in one P? then, how many in 2? how many in 3? ... so, how many in 2.5?
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A rectangular box whose base is twice as long as it wide has volume of 256 cm^3. Material for the top costs 10 centavos per
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one post is enough for one problem.
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A rectangular box whose base is twice as long as it wide has volume of 256 cm^3. Material for the top costs 10 centavos per
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x*2x*h = 256, so h = 128/x^2 So the cost c(x) = 10*2x^2 + 5*2x^2 + 5*2(xh+2xh) = 30x^2 +
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a closed rectangular box whose base is twice as long as it is wide has a volume of 36000 cm^3.the material for the top cost 10
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The question said that the bottom's price is the same with the sides price. so basically you need to
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Y is partially constant and partially varies as x , when x is equal to 1 ,y equal to 7 when x equal to minus ,y is equal to 11
Top answer:
y = mx+b to find m and b, solve m+b=7 -?m+b = 11 when you decide what x is when y=11
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¿Cómo son las monedas de pesos mexicanos?We had to do a reading and type the answers-not sure about this question
Hay monedas
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I'll send this to SraJMcGin.
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Simplify the rational expression. State any restrictions on the variable.
(t^2 + t - 6)/(t^2 - 9) (t - 2)/(t-3), t not equal 3, t
Top answer:
The simplified rational expression is (t+2)/(t-3), with restrictions t cannot equal 3.
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1) When will the dependent variable in the equation y=√x+4-3 equal or exceed to 4?
A) x > or equal to -0.17 B) x > or equal to
Top answer:
#1 √(x+4)-3 >= 4 √(x+4) >= 7 x+4 >= 49 x >= 53 #2 t = √(d/16), so we want (using t in seconds)
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By graphing the system of constraints, find the values of x and y that maximize the objective function.
2 less than or equal to x
Top answer:
so, did you graph the lines? Evaluate 3x+2y at each vertex. Pick the maximum value where do you get
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