X

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..-
…-
….-
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…………………..---------Y

-The loss of gravitational potential energy Ep of the rider and motorbike from X to Y is 4.66x10^4
-The kinetic energy Ek of the rider and motorbike at Y is 8.55x10^4.

Explain why the Ek of the rider and motorbike at Y is greater than the Ep of the rider and motorbike from X toY. Please explain in detail and clearly.

the rider/bike was already moving at X (like driving off a cliff)

so the Ek gain from the Ep loss is added to the initial Ek of the rider/bike

To understand why the kinetic energy (Ek) of the rider and motorbike at Y is greater than the gravitational potential energy (Ep) of the rider and motorbike from X to Y, we need to understand the properties and relationships between these two forms of energy.

1. Gravitational Potential Energy (Ep):
Gravitational potential energy is the energy possessed by an object due to its position in a gravitational field. It depends on the height of the object above a reference point, usually the ground. As the object gains height, its potential energy increases, and as it loses height, its potential energy decreases.

In the given scenario, the rider and motorbike are moving from point X to point Y. The loss of gravitational potential energy (Ep) from X to Y is given as 4.66x10^4.

2. Kinetic Energy (Ek):
Kinetic energy is the energy possessed by an object due to its motion. It depends on the mass of the object and its velocity. The formula for kinetic energy is Ek = 0.5 * mass * velocity^2.

In the given scenario, the kinetic energy (Ek) of the rider and motorbike at point Y is given as 8.55x10^4.

Now, let's explain why Ek at Y is greater than Ep from X to Y:

As the rider and motorbike move from X to Y, there is a loss of potential energy, which is converted into other forms, such as kinetic energy. This conversion occurs because, as the rider and motorbike lose height, their potential energy decreases, and an equivalent amount of energy is transferred into kinetic energy.

Therefore, for the kinetic energy (Ek) at Y to be greater than the potential energy (Ep) from X to Y, the loss of potential energy (4.66x10^4) must be less than the gain in kinetic energy (8.55x10^4).

In simpler terms, the rider and motorbike have gained more kinetic energy than the potential energy they lost during their downward motion. This implies that they have gained additional energy from another source, such as the engine or other external factors, which contributes to the increased kinetic energy at point Y.

In conclusion, the kinetic energy (Ek) of the rider and motorbike at point Y is greater than the potential energy (Ep) from X to Y because some other source, like the engine, has added additional energy to the system, resulting in a net gain of kinetic energy.