The length of a room is double its breath. Its height is 5m the area of four walls ( including the door and windows) is 210sq m. Find its volume solve this sum

Thanks for giving such a great answer

width --- x m

length --- 2x m
height ---- 5 m

total surface area of the 4 walls
= (5)(2x) + (5)(x) + (5)(2x) + (5)(x)
= 30x

But in your un-punctuated sentence you say that this is 210 m^2
30x = 210
x = 7

so the room is 7m by 14m by 5 m
for a volume of 490 m^3

"Find its volume solve this sum" ----> I hope your text did not ask the question in that way.

helpful for me .

That's not good

To find the volume of the room, we need to know its length, breadth, and height.

Let's start by assigning variables to the unknowns:
Let L be the length of the room.
Let B be the breadth of the room.

We are given the following information:
"The length of a room is double its breadth."
This can be represented by the equation: L = 2B.

"The height is 5m."
We can represent the height as H = 5.

"The area of four walls (including the door and windows) is 210sq m."
The surface area of the four walls (excluding the floor and ceiling) can be calculated by adding the areas of each wall. Since the room is rectangular, the surface area is calculated using the formula: 2(L + B) * H.

According to the problem, 2(L + B) * H = 210.

Now let's substitute the value of L from the first equation into the second equation:

2(2B + B) * 5 = 210.
Simplifying this equation, we get:
10B + 10B = 210.
20B = 210.
Dividing both sides by 20:
B = 10.5.

Now that we have the value of B, we can substitute it back into the first equation to find L:
L = 2B = 2 * 10.5 = 21.

Therefore, the length of the room is 21m, and the breadth is 10.5m.

Finally, to find the volume of the room, we multiply the length (L), breadth (B), and height (H):
Volume = L * B * H = 21 * 10.5 * 5 = 1102.5 cubic meters.

Hence, the volume of the room is 1102.5 cubic meters.

Better

VERY BORNIG BUT ITS GOOD