The population of Andhra Pradesh was 5.4 * 10^7 in 1988. If the population was growing at a constant rate of 2.4% per annum, what was the population in 2008 A.D ( Given that (1.024)^20 = 1.60694)
To find the population of Andhra Pradesh in 2008, we need to use the formula for compound interest:
P = P_0 * (1 + r)^n
Where:
P is the final population
P_0 is the initial population
r is the growth rate per period
n is the number of periods
Given:
P_0 = 5.4 * 10^7 (population in 1988)
r = 0.024 (2.4% growth rate per annum)
n = 2008 - 1988 = 20 (number of years)
Substituting these values into the formula:
P = (5.4 * 10^7) * (1 + 0.024)^20
Now, let's plug it into a calculator or solve it step by step:
1 + 0.024 = 1.024
So, the equation becomes:
P = (5.4 * 10^7) * (1.024)^20
Using the given value of (1.024)^20 = 1.60694:
P = (5.4 * 10^7) * 1.60694
Calculating further:
P = 8.71 * 10^7
Therefore, the population of Andhra Pradesh in 2008 was approximately 8.71 * 10^7.
Question ka answers
just multiply your 1988 population by 1.60694
why do you think they gave you that number?