physics

A 2.63 kg ball is dropped from the roof of a building 180.6 m high. While the ball is falling to Earth, a horizontal wind exerts a constant force of 13.0 N on the ball. How long does it take to hit the ground? The acceleration of gravity is 9.81 m/s2 .
How far from the building does the ball hit the ground?
What is the speed when it hits the ground?

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asked by jay
  1. Vertical problem:
    (1/2) m V^2 = m g h
    V = sqrt (2 g h) at bottom
    V =sqrt(2*9.81*180.6

    time at ground:
    average v = V/2
    so
    t = 180.6/v = time at ground

    Horizontal problem (use t from above)
    a = 13.0/2.63
    u = a t
    d = (1/2) a t^2

    speed = sqrt(u^2+V^2)

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    posted by Damon

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