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What mass of iron contains the same number of atoms as 70.05 g of nitrogen?

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  1. If you know how to do these you should show us and we can check the answer and/or method for you. But we don't DO the work.
    First, determine the number of atoms in 70.05 g N2, then convert that to grams Fe.

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  2. i got 3.011 x 10^24 atoms N

    how do i convert this to Fe?

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  3. I see that worked for the C6H12O6 problem we worked on below. Let this be a learning experience for you. Just leave all the intermediate calculations, if possible, in the computer, and make the final rounding just once; otherwise, we get rounding errors and the more intermediate steps we use the more errors.
    If you MUST copy a number down (for subtraction, addition, or something else), I usually copy MORE places (more significant figures) than I am allowed, do the math, then make a final rounding to the correct number of s.f. last.

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  4. okay thanks

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  5. i got 3.011 x 10^24 atoms N

    how do i convert this to Fe?

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  6. 70.05 g N2 has a molar mass of 28.01348.
    70.05 x (1 mol/28.01348) x (2 atoms N/mol N2) x (6.022 x 10^23 atoms/mol) = 3.0117 x 10^24 atoms nitrogen.

    1 mol Fe contains 6.022 x 10^23 atoms.
    1 mol Fe has a mass of 55.847 grams.
    If you're unconfortable with the factor label method, use ratio and proportion.
    (Note above that I usually make a habit of using all of the numbers in a conversion, but especially here, I used 6.022 x 10^23 [instead of 6.02] because 70.05 has 4 s.f. and I wanted Avogadro's number to have 4 s.f., too.)

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